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Comments
Good to see you experimenting with new things.
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Did you know that:
E^2 = p^2c^2)+([<delta>m^2]c^4.
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c")].
when p=0 (in eq 1, or 2, whichever you find simpler)
E=mc^2........
(In reality, p can never=0, so E should, realistically not be =mc^2, )
beautiful, I love this dreamy feeling.
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"I'll tumble for ya"
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le geste le plus fou, est le geste le plus beau
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le geste le plus fou, est le geste le plus beau
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le geste le plus fou, est le geste le plus beau
--
le geste le plus fou, est le geste le plus beau
--
"I'll tumble for ya"
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